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Exam Code: H13-531_V2.0

Exam Name: HCIE-Cloud Computing (Written) V2.0

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NEW QUESTION: 1
Refer to the exhibit. Given the output from the show ip eigrp topology command, which router is the feasible successor?


A. Exhibit C
B. Exhibit D
C. Exhibit B
D. Exhibit A
Answer: C
Explanation:
The AD of the feasible successor must be smaller than the FD of successor. From the output
provided in the exhibit, we know that the FD of successor is 41152000.
In the option A, the AD is 41640000
In the option B , the AD is 128256
In the option C, the AD is 46354176
In the option D, the AD is 46251776.
Through comparison, we know that only the AD in option B is smaller than FD, so B can be used
as feasible successor.
Successor: A successor for a particular destination is a next hop router that satisfies these two
conditions:
it provides the least distance to that destination
it is guaranteed not to be a part of some routing loop
The first condition can be satisfied by comparing metrics from all neighboring routers that
advertise that particular destination, increasing the metrics by the cost of the link to that respective
neighbor, and selecting the neighbor that yields the least total distance. The second condition can
be satisfied by testing a so-called Feasibility Condition for every neighbor advertising that
destination. There can be multiple successors for a destination, depending on the actual topology.
The successors for a destination are recorded in the topology table and afterwards they are used
to populate the routing table as next-hops for that destination.
Feasible successor: A feasible successor for a particular destination is a next hop router that
satisfies this condition:
it is guaranteed not to be a part of some routing loop
This condition is also verified by testing the Feasibility Condition.
Thus, every successor is also a feasible successor. However, in most references about EIGRP the
term "feasible successor" is used to denote only those routers which provide a loop-free path but
which are not successors (i.e. they do not provide the least distance). From this point of view, for a
reachable destination there is always at least one successor, however, there might not be any
feasible successors.
A feasible successor provides a working route to the same destination, although with a higher
distance. At any time, a router can send a packet to a destination marked "Passive" through any of
its successors or feasible successors without alerting them in the first place, and this packet will be
delivered properly. Feasible successors are also recorded in the topology table. AD : Advertised Distance (AD) is the distance to a particular destination as reported by a router to its neighbors. This distance is sometimes also called a Reported Distance and is equal to the current lowest total distance through a successor. FD. A Feasible Distance (FD) is the lowest known distance from a router to a particular destination since the last time the route went from Active to Passive state. It can be expressed in other words as a historically lowest known distance to a particular destination. While a route remains in Passive state, the FD is updated only if the actual distance to the destination decreases, otherwise it stays at its present value. On the other hand, if a router needs to enter Active state for that destination, the FD will be updated with a new value after the router transitions back from Active to Passive state. This is the only case when the FD can be increased. The transition from Active to Passive state in effect marks the start of a new history for that route.

NEW QUESTION: 2
You are working on a design that includes Avaya Aura Presence Services.
Which statement regarding the Presences Services deployment is true?
A. It can only be installed on one dedicated (closed) Avaya Breeze instance.
B. It requires one or more general purpose (open) Avaya Breeze instances.
C. It always requires one or more dedicated (closed) Avaya Breeze instances.
D. It does not require dedicated (closed) Avaya Breeze instances.
Answer: D

NEW QUESTION: 3
Helmut Humm, manager at a large U.S. firm, has just been assigned to the capital budgeting area to replace a person who left suddenly. One of Humm's first tasks is to calculate the company's weighted average cost of capital (WACC) - and fast! The CEO is scheduled to present to the board in half an hour and needs the WACC - now! Luckily, Humm finds clear notes on the Target capital component weights in the current workpapers. Unfortunately, all he can find for the cost of capital components is some handwritten notes. He can make out the numbers, but not the corresponding capital component. As time runs out, he has to guess.
Here is what Humm deciphered:
If Humm guesses correctly, the WACC is:
A. 11.0%.
B. 10.1%.
C. 9.7%.
D. 10.4%.
Answer: D
Explanation:
Explanation/Reference:
Explanation:
If Humm remembers to order the capital components from cheapest to most expensive, he can calculate WACC. The order from cheapest to most expensive is: debt, preferred stock (which acts like a hybrid of debt and equity), retained earnings, and common stock. (Remember that internal equity - retained earnings is cheaper than external equity -common equity due to floatation costs.) Then, using the formula for WACC = (wd)(kd) + (wps)(kps) + (ws)(ks)+ (we)(ke) where wd, wps, wsandweare the weights used for debt, preferred stock, retained earnings, and common equity.
WACC = (0.30 * 6.0%) + (0.20 * 8.5%) + (0.15 * 11.00%) + (0.35 * 15.0%) =10.4%.


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